paulrfrancisco
Petty Officer 1st Class
- Joined
- Oct 25, 2004
- Messages
- 341
First forgive me for getting off topic and perhaps being dense, but I've been following the Captianloud thread about the harmonic balancer of the 4/3L V6, and read the .pdf file near the end where it gives the specs on the 4.3L. I was amazed at the 4" bore and 4" stroke geometry of this motor so I got to thinking about the math to figure the cu in displacement. And calculating this out it comes to 301ci. (PI * Radius squared (bore 4"/2) * 4" (stroke) * 6 (# of Cyl) = 301 cu. in. The 4.3L is like 268ci. No? Where 4.3L divided by 62.5 = 268ci. Am I missing something? 1 cubic inch (1*1*1) is = to 16.38 cu centermeters (2.54cm * 2.54cm * 2.54cm)... Right?<br /><br />Ok I have too much time on my hands....LOL