Re: old vs new and torque
I'll venture on that one. My answer is, "if your compression ratio is similar, in theory, yes." So, to leverage our earlier discussion, horsepower is measureable via a dyno. The work the dyno pump is doing is displayed as a function of fluid velocity (flow)and pressure over time (Power = Work/time). If you look at the units, horsepower can be expressed as (distance X Force)/time. A common unit is 1 hp = 550 ft-lbs/sec or 6600 in-lbs/sec. Now, pressure is in Force/area. A common one is lbs/sq in. Flow is in volume/time. Let's use (cu in/sec). A prop shaft spins a pump that creates both pressure and flow(controlled by the operator) Take pressure X flow, and you get (lbs/sq in) X (cu in/sec) .. you get lbs -in/sec (horsepower!). So, if you create 2000 psi and a flow of 66 cu in/sec, you have 132,000 lb-in/sec. Divide by 6600 and you get 20 hp. Long way to say torque is not measured (sorry for the long diatribe).<br />So, torque (as I understand it), cannot be measured, but is the cumulative perpendicular force applied to the journals times the journal length. It's constantly changing over time, as the pistons move. displacement is the area of the cylinder X the piston travel. Your greater-displacement motor must either have a greater cylinder area (thus more gas/air and more force on the piston), or greater travel distance, which is related to the journal length. If either increases, the torque MUST increase. Whew .. hope that wasn't too boring .. and it's just my guess. I'm thinking the only caveat is if greater cylinder area does not create greater force on the piston due to a heavier piston, lower compression, etc.