Re: Horse power question
Both outboards would be producing 20 net HP at the crankshaft. Both are working equally as hard. The fact one outboard has the potential to produce 40 hp and one doesn't is irrelevant. The object would be do find out which outboard is most efficient at 20 HP, or in other words, which outboard burns the least amount of fuel to produce the same amount of work.<br /><br />When looking at efficiency, you have to look at thermal efficiency and mechanical efficiency under exactly the same conditions.<br /><br />Thermal efficiency is heat efficiency, and based on how much of the energy (ability to do work) of the burning fuel is converted into horsepower. Each outboard has a unique thermal efficiency based on its cooling system, lubrication system, exhaust system, and operating rpm, etc.<br /><br />Mechanical efficiency is based on the relationship of power developed within the engine to the actual horsepower at the crankshaft. Again, each outboard has a unique mechanical efficiency based on internal friction, gear reduction, operating RPM, etc.<br /><br />A larger outboard must overcome greater internal frictions, larger internal forces, compensate for its extra weight and drag, etc. It probably has less mechanical efficiency at 20 HP, but greater thermal efficiency. A smaller outboard must obviously work harder to get the same amount of work done as the larger displacement outboard, but most likely it does it with better mechanical efficiency and worse thermal efficiency.<br /><br />The only realistic solution to this question is to run both outboards under the exact same conditions, doing the exact same amount of work, and measure their fuel usage.<br /><br />My bet is that the smaller 20 HP outboard will be more efficient. After all, it is designed for 20 HP use. The larger 40 HP outboard will simply be waisting a lot of its efficiency running at 20 HP. It is designed for 40 HP use.
