jlinder
Lieutenant Junior Grade
- Joined
- Jul 5, 2004
- Messages
- 1,086
Re: power drop from battery
Sorry, but you have it wrong. This is something that people get confused.
The heat created in the wire is due to the voltage ACROSS THE WIRE times the current. It has nothing to do with the voltage across the other elements in the circuit like the battery or the load. If I pass 20 amps through a 10 ft. long 12 gauge wire the amount heat generated is based on the voltage drop (.653 volts in this case x 20 amp = 13 watts).
You might have it connected to a 12 v battery or you could have 440v AC supply - it does not matter to the wire.
Yes, for the 12v supply you would have 20A supplied at 11.35v to the load and it would dissipate about 227watts, and at 440v you would dissipate about 880 watts, but that is in the load (or from the supply).
No matter what you still have 13 watts of heat in the wire.
Sorry but that is incorrect because: The 12V DC circuit supplying current does create less heat in the same conduit than a 110V AC voltage supply, provided that the currents are the same.
Sorry, but you have it wrong. This is something that people get confused.
The heat created in the wire is due to the voltage ACROSS THE WIRE times the current. It has nothing to do with the voltage across the other elements in the circuit like the battery or the load. If I pass 20 amps through a 10 ft. long 12 gauge wire the amount heat generated is based on the voltage drop (.653 volts in this case x 20 amp = 13 watts).
You might have it connected to a 12 v battery or you could have 440v AC supply - it does not matter to the wire.
Yes, for the 12v supply you would have 20A supplied at 11.35v to the load and it would dissipate about 227watts, and at 440v you would dissipate about 880 watts, but that is in the load (or from the supply).
No matter what you still have 13 watts of heat in the wire.