Re: Start button
When you say "ignition" are you referring to the switch I have marked "Run" in my diagram? I'm assuming as of right now you are...I could be wrong.
Here are my assumptions on how things work. I'm hoping to clarify that I am right or wrong.
1. With the DPDT (on-on) type switch when one side of the switch is closed the other side is open.
2. Simply put, in order to kill the engine you have to connect one (or both, not sure here) of the white or salmon wires...which are connected to the ignition points, to a ground wire. I'm assuming these wires would be the ignition wires, since they are connected to that part of the system. The switch does this by running a ground into the same side on the contacts as the white and salmon wires, just in the middle position.
Here is how I got to where I am.
1. Flip the switch to the "Run" position, which provides power to the "Start" button. This is done by routing the 12v+ through the switch labeled run in my diagram and then to the start button. This also provides power to the choke switch.
2. Press the choke button. This activates the choke solenoid via a gray wire labeled in the diagram going to "C" This solenoid is grounded up where it is connected to the engine housing.
3. Press the start button. This delivers power to the starter solenoid via the yellow wire routed through "B". Again this is grounded up where it connects to the engine housing. It is also connected to the battery via what look like 6ga or 8ga wires (through the wire harness)
Now the engine is running and its time to kill it to catch a giant fish
1. Flip the switch labeled run in the diagram to the "Kill" position. This connects the white and salmon wires with the ground wire. Which I think, if I understand right, is what needs to happen in order to kill the engine.
I will look more into the relay to make sure I have that figured correctly.
I don't know if all I said above is correct but these are my assumptions that lead me to where I am now. I'm hoping to get those corrected if I am wrong.
When you say "ignition" are you referring to the switch I have marked "Run" in my diagram? I'm assuming as of right now you are...I could be wrong.
Here are my assumptions on how things work. I'm hoping to clarify that I am right or wrong.
1. With the DPDT (on-on) type switch when one side of the switch is closed the other side is open.
2. Simply put, in order to kill the engine you have to connect one (or both, not sure here) of the white or salmon wires...which are connected to the ignition points, to a ground wire. I'm assuming these wires would be the ignition wires, since they are connected to that part of the system. The switch does this by running a ground into the same side on the contacts as the white and salmon wires, just in the middle position.
Here is how I got to where I am.
1. Flip the switch to the "Run" position, which provides power to the "Start" button. This is done by routing the 12v+ through the switch labeled run in my diagram and then to the start button. This also provides power to the choke switch.
2. Press the choke button. This activates the choke solenoid via a gray wire labeled in the diagram going to "C" This solenoid is grounded up where it is connected to the engine housing.
3. Press the start button. This delivers power to the starter solenoid via the yellow wire routed through "B". Again this is grounded up where it connects to the engine housing. It is also connected to the battery via what look like 6ga or 8ga wires (through the wire harness)
Now the engine is running and its time to kill it to catch a giant fish
1. Flip the switch labeled run in the diagram to the "Kill" position. This connects the white and salmon wires with the ground wire. Which I think, if I understand right, is what needs to happen in order to kill the engine.
I will look more into the relay to make sure I have that figured correctly.
I don't know if all I said above is correct but these are my assumptions that lead me to where I am now. I'm hoping to get those corrected if I am wrong.