wire2
Lieutenant Commander
- Joined
- Jun 25, 2007
- Messages
- 1,584
Re: Does this sound right about a coil and resistance?
Compare it to a garden hose with the tap just barely on, assume city pressure of 50 psi. If the nozzle is not opened, the pressure at the nozzle will be 50 psi within a few seconds. If you kink the hose (but not completely sealed) the nozzle pressure will still be at 50. Thats comparable to 2 resisters in a circuit.
Until you open the nozzle, and have flow (current) Now there will be a drop in pressure. (voltage)
A good Fluke VOM has 11 Megohms input resistance, so the load presented is negligible.
EDIT
It occured to me, some people are not familiar with Ohm's law. Briefly;
It states that E = I/R. where E is voltage (Electromotive force), I is current, and R is resistance.
If you measure across a resistor in a circuit with no current, and say, a 1,000 Ω resistor, it becomes E = 0/1000. Zero divided by 1000 is still zero, and E is also zero (the voltage across the resistor). There can be 12 volts, or 100 volts dc on the circuit, it makes no difference.
No. Ohm's law will prove it. Without current, there is no voltage drop.i think there should still be a drop. you don't need current in the circuit to measure voltage (except for what the voltmeter draws).
Compare it to a garden hose with the tap just barely on, assume city pressure of 50 psi. If the nozzle is not opened, the pressure at the nozzle will be 50 psi within a few seconds. If you kink the hose (but not completely sealed) the nozzle pressure will still be at 50. Thats comparable to 2 resisters in a circuit.
Until you open the nozzle, and have flow (current) Now there will be a drop in pressure. (voltage)
A good Fluke VOM has 11 Megohms input resistance, so the load presented is negligible.
EDIT
It occured to me, some people are not familiar with Ohm's law. Briefly;
It states that E = I/R. where E is voltage (Electromotive force), I is current, and R is resistance.
If you measure across a resistor in a circuit with no current, and say, a 1,000 Ω resistor, it becomes E = 0/1000. Zero divided by 1000 is still zero, and E is also zero (the voltage across the resistor). There can be 12 volts, or 100 volts dc on the circuit, it makes no difference.